Problem B: Bitset I - Bit Flag

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Time Limit $2$ 秒/Second(s) Memory Limit $512$ 兆字节/Megabyte(s)
提交总数 $53$ 正确数量 $24$
裁判形式 标准裁判/Standard Judge 我的状态 尚未尝试
难度 分类标签 STL

A state with nn flags of ON or OFF can be represented by a sequence of bits where 0,1,...,n10,1,...,n−1 -th flag corresponds to 1 (ON) or 0 (OFF). The state can be managed by the corresponding decimal integer, because the sequence of bits is a binary representation where each bit is 0 or 1.

Given a sequence of bits with 64 flags which represent a state, perform the following operations. Note that each flag of the bits is initialized by OFF.

  • test(i): Print 1 if ii-th flag is ON, otherwise 0
  • set(i): Set ii-th flag to ON
  • clear(i): Set ii-th flag to OFF
  • flip(i): Inverse ii-th flag
  • all: Print 1 if all flags are ON, otherwise 0
  • any: Print 1 if at least one flag is ON, otherwise 0
  • none: Print 1 if all flags are OFF, otherwise 0
  • count: Print the number of ON flags
  • val: Print the decimal value of the state


The input is given in the following format.

qq query1query1 query2query2 : queryqqueryq 

Each query queryiqueryi is given in the following format:

0 ii 

or

1 ii 

or

2 ii 

or

3 ii 

or

4

or

5

or

6

or

7

or

8

The first digit 01,...,8 represents the operation test(i), set(i), clear(i), flip(i), all, any, none, count or val respectively.


		


	


Print the result in a line for each test, all, any, none, count and val operation.
14
1 0
1 1
1 2
2 1
0 0
0 1
0 2
0 3
3 3
4
5
6
7
8
1
0
1
0
0
1
0
3
13

Constraints

  • 1q200,000 1≤q≤200,000
  • 0i<64 0≤i<64



AOJ